document.write( "Question 1101735: A coin jar contains nickels, dimes, and quarters. There are 66 coins in all. There are 8 more nickels than quarters. The value of the dimes is $3.20 less than the value of the quarters. How many quarters are in the jar?
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Algebra.Com's Answer #716415 by greenestamps(13209)\"\" \"About 
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\n" ); document.write( "The first tutor had an error in his algebra; the second tutor didn't read the problem correctly. There is a solution to your problem.

\n" ); document.write( "Let the number of quarters be q;
\n" ); document.write( "then the number of nickels is q+8.
\n" ); document.write( "Then, since the total number of coins is 66, the number of dimes is \"66-%28q%2B%28q%2B8%29%29+=+58-2q\"

\n" ); document.write( "We are told the value of the dimes is $3.20 less than the value of the quarters. Writing the equation in cents instead of dollars:
\n" ); document.write( "\"10%2858-2q%29+=+25q+-+320\"
\n" ); document.write( "\"580-20q+=+25q-320\"
\n" ); document.write( "\"900+=+45q\"
\n" ); document.write( "\"q+=+20\"
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\n" ); document.write( "The number of quarters is 20; so the number of nickels is 28; so the number of dimes is 18.
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