document.write( "Question 1101705: an estate value at $6000 is divided among three sons, Albert, Brian and Charles in the ratio 1:2:3 respectively. Calculate the amount each receives.
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Algebra.Com's Answer #716354 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let x be the measure of the common part.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then A received x dollars;\r\n" ); document.write( "\r\n" ); document.write( "B received 2x dollars;\r\n" ); document.write( "\r\n" ); document.write( "and C received 3x dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "So the three received x + 2x + 3x = 6x dollars, and this sum is 6000 dollars:\r\n" ); document.write( "\r\n" ); document.write( "6x = 6000 dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hence, x = 1000 dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus A received $1000, B received $2000, and C received 3000 dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Check. 1000 + 2000 + 3000 = 6000. ! Correct !\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |