document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101690>Question 1101690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two towns A and B ate 42 km apart. A person starts from A,walks at 4 km/h towards B and meets another person coming from B towards A after 6 hours. Find the rate at which the second person is walking, if both persons start walking at the same time.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716302 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s = the speed of person B<BR>\n" );
document.write( "Since they are walking towards each other, their relative speed is 4 + s.<BR>\n" );
document.write( "At this relative speed, they cover a distance of 42 km in 6 hrs.<BR>\n" );
document.write( "Therefore 4 + s = 42/6 = 7<BR>\n" );
document.write( "Thus s = 7 - 4 = 3 km/h </SPAN>\n" );
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