document.write( "Question 1101674: Mr. Jackson is filling planter boxes with soil. He has soil that is 19% sand, and he buys 8 pounds of a commercial potting soil that is 22% sand. He mixes some of his soil with the 8 pounds of commercial potting soil. The resulting soil mixture is 21% sand. How many pounds of his soil did Mr. Jackson use?\r
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document.write( "A. 12 lb
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document.write( "B. 4 lb
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document.write( "C. 2 lb
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document.write( "D. 8 lb \n" );
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Algebra.Com's Answer #716272 by richwmiller(17219) You can put this solution on YOUR website! Let C denote the 19% solution and D denote the final 21% solution. \n" ); document.write( "We have 8 lbs of 22% solution. \n" ); document.write( "Using the method of alligation. \n" ); document.write( "1= 21 - 22 \n" ); document.write( "2= 19 - 21 \n" ); document.write( "E.g. There are 2 parts of C for every 1 parts of D \n" ); document.write( "then there are 8 parts of z, since (2/1)=8/z \n" ); document.write( "x= 4= 8/(2/1) lbs of 19% solution to add to your 8 lbs of 22% solution. \n" ); document.write( "y= 12= (8+4) lbs of the final 21% solution. \n" ); document.write( "check \n" ); document.write( "0.19 * 4 + 0.22 * 8 = 0.21*(8+4) \n" ); document.write( "0.76 + 1.76 = 0.21*(12) \n" ); document.write( "2.52 = 2.52 \n" ); document.write( "ok \n" ); document.write( " \r\n" ); document.write( "22 2 8 lbs of 22% solution\r\n" ); document.write( " 21 12 lbs of 21% solution\r\n" ); document.write( "19 1 1/2*8=4 lbs of 19% solution\r\n" ); document.write( " 3\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |