document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101669>Question 1101669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Kang mixes an 80% sugar cinnamon-flavored solution with a 95% sugar cherry-flavored solution to make 15 gallons of a new product. The new product is 90% sugar. How much of the cherry-flavored solution did he use?\r<BR>\n" );
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document.write( "A. 12 gal<BR>\n" );
document.write( "B. 14 gal<BR>\n" );
document.write( "C. 10 gal<BR>\n" );
document.write( "D. 5 gal </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716270 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A denote the 95% solution and B denote the 80% solution which we have.<BR>\n" );
document.write( "Let C denote the 90% solution which we want.<BR>\n" );
document.write( "Using the method of alligation.<BR>\n" );
document.write( "10= 90 - 80<BR>\n" );
document.write( "5= 95 - 90<BR>\n" );
document.write( "E.g. There are 10 parts of A plus 5 parts of B<BR>\n" );
document.write( "Then 10+5=15 parts total<BR>\n" );
document.write( "10/15=0.66666667<BR>\n" );
document.write( "0.66666667*15=10<BR>\n" );
document.write( "10 gal of 95% solution.\r<BR>\n" );
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document.write( "15 gal-10 gal=5 gal<BR>\n" );
document.write( "5 gal of 80% solution.<BR>\n" );
document.write( "or<BR>\n" );
document.write( "5/15=0.33333333<BR>\n" );
document.write( "0.33333333*15=5 gal<BR>\n" );
document.write( "5 gal of 80% solution.<BR>\n" );
document.write( "check<BR>\n" );
document.write( "0.8 * 5 + 0.95 * 10 = 0.9*15<BR>\n" );
document.write( "4.0 + 9.5 = 13.5<BR>\n" );
document.write( "13.5 = 13.5<BR>\n" );
document.write( "ok\r<BR>\n" );
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document.write( " </SPAN>\n" );
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