document.write( "Question 98453: These 3 problems do not come from a book but I really need help with them!
\n" ); document.write( "If you can solve them as soon as possible, I would greatly appreciate it.
\n" ); document.write( "Here they are:
\n" ); document.write( "#1:
\n" ); document.write( "Write the equation of the line passing through the points listed below. Write the final answer in the slope-intercept form y = mx + b. If the slope (m) or the y-intercept (b) are not integers, fractions must be used. \r
\n" ); document.write( "\n" ); document.write( "(-1, 8); (9, 2)\r
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\n" ); document.write( "#2:
\n" ); document.write( "A line passes through the origin and the point (-6, 4).\r
\n" ); document.write( "\n" ); document.write( "Write the equation of the line that passes through (-6, 4) and is perpendicular to the given line.\r
\n" ); document.write( "\n" ); document.write( "Write the final answer in the slope-intercept form y = mx + b.
\n" ); document.write( "(The slope and y-intercept must be written as fractions, when needed).\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "#3:
\n" ); document.write( "Write the equation for the line perpendicular to
\n" ); document.write( "2x - 5y = 5 and passes through the point (-2, -5).
\n" ); document.write( "Enter the variable expression Ax + By separately from the constant term C.
\n" ); document.write( "Your response should be given in standard form where A, B and C are the smallest possible integers and A > 0.\r
\n" ); document.write( "\n" ); document.write( "Thanks so much.
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Algebra.Com's Answer #71626 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
These explanations are quite lengthy, so here's a mini table of contents\r
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#1
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Go to top\r
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\n" ); document.write( "\n" ); document.write( "\"#1:
\n" ); document.write( "Write the equation of the line passing through the points listed below. Write the final answer in the slope-intercept form y = mx + b. If the slope (m) or the y-intercept (b) are not integers, fractions must be used.
\n" ); document.write( "(-1, 8); (9, 2)\"\r
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\n" ); document.write( "\n" ); document.write( "First lets find the slope through the points (\"-1\",\"8\") and (\"9\",\"2\")\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula (note: is the first point (\"-1\",\"8\") and is the second point (\"9\",\"2\"))\r
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\n" ); document.write( "\n" ); document.write( "\"m=%282-8%29%2F%289--1%29\" Plug in \"y%5B2%5D=2\",\"y%5B1%5D=8\",\"x%5B2%5D=9\",\"x%5B1%5D=-1\" (these are the coordinates of given points)\r
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\n" ); document.write( "\n" ); document.write( "\"m=+-6%2F10\" Subtract the terms in the numerator \"2-8\" to get \"-6\". Subtract the terms in the denominator \"9--1\" to get \"10\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=-3%2F5\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the slope is\r
\n" ); document.write( "\n" ); document.write( "\"m=-3%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point-slope formula to find the equation of the line:\r
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\n" ); document.write( "\n" ); document.write( "------Point-Slope Formula------
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is one of the given points\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-8=%28-3%2F5%29%28x--1%29\" Plug in \"m=-3%2F5\", \"x%5B1%5D=-1\", and \"y%5B1%5D=8\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-8=%28-3%2F5%29%28x%2B1%29\" Rewrite \"x--1\" as \"x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-8=%28-3%2F5%29x%2B%28-3%2F5%29%281%29\" Distribute \"-3%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-8=%28-3%2F5%29x-3%2F5\" Multiply \"-3%2F5\" and \"1\" to get \"-3%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-3%2F5%29x-3%2F5%2B8\" Add \"8\" to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-3%2F5%29x%2B37%2F5\" Combine like terms \"-3%2F5\" and \"8\" to get \"37%2F5\" (note: if you need help with combining fractions, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line which goes through the points (\"-1\",\"8\") and (\"9\",\"2\") is:\"y=%28-3%2F5%29x%2B37%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "The equation is now in \"y=mx%2Bb\" form (which is slope-intercept form) where the slope is \"m=-3%2F5\" and the y-intercept is \"b=37%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-3%2F5%29x%2B37%2F5\" and plot the points (\"-1\",\"8\") and (\"9\",\"2\"), we get this: (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-3%2F5%29x%2B37%2F5\" through the points (\"-1\",\"8\") and (\"9\",\"2\")\r
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\n" ); document.write( "\n" ); document.write( "Notice how the two points lie on the line. This graphically verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( "\"A line passes through the origin and the point (-6, 4).
\n" ); document.write( "Write the equation of the line that passes through (-6, 4) and is perpendicular to the given line.
\n" ); document.write( "Write the final answer in the slope-intercept form y = mx + b.
\n" ); document.write( "(The slope and y-intercept must be written as fractions, when needed). \"\r
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\n" ); document.write( "\n" ); document.write( "First find the equation of the line through the points (0,0) (the origin) and (-6,4)\r
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\n" ); document.write( "\n" ); document.write( "First lets find the slope through the points (\"0\",\"0\") and (\"-6\",\"4\")\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula (note: is the first point (\"0\",\"0\") and is the second point (\"-6\",\"4\"))\r
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\n" ); document.write( "\n" ); document.write( "\"m=%284-0%29%2F%28-6-0%29\" Plug in \"y%5B2%5D=4\",\"y%5B1%5D=0\",\"x%5B2%5D=-6\",\"x%5B1%5D=0\" (these are the coordinates of given points)\r
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\n" ); document.write( "\n" ); document.write( "\"m=+4%2F-6\" Subtract the terms in the numerator \"4-0\" to get \"4\". Subtract the terms in the denominator \"-6-0\" to get \"-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=-2%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the slope is\r
\n" ); document.write( "\n" ); document.write( "\"m=-2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point-slope formula to find the equation of the line:\r
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\n" ); document.write( "\n" ); document.write( "------Point-Slope Formula------
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is one of the given points\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-0=%28-2%2F3%29%28x-0%29\" Plug in \"m=-2%2F3\", \"x%5B1%5D=0\", and \"y%5B1%5D=0\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-0=%28-2%2F3%29x%2B%28-2%2F3%29%280%29\" Distribute \"-2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-0=%28-2%2F3%29x%2B0\" Multiply \"-2%2F3\" and \"0\" to get \"0%2F3\". Now reduce \"0%2F3\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x%2B0%2B0\" Add \"0\" to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x%2B0\" Combine like terms \"0\" and \"0\" to get \"0\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line which goes through the points (\"0\",\"0\") and (\"-6\",\"4\") is:\"y=%28-2%2F3%29x\"\r
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\n" ); document.write( "\n" ); document.write( "The equation is now in \"y=mx%2Bb\" form (which is slope-intercept form) where the slope is \"m=-2%2F3\" and the y-intercept is \"b=0\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-2%2F3%29x\" and plot the points (\"0\",\"0\") and (\"-6\",\"4\"), we get this: (note: if you need help with graphing, check out this
solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-2%2F3%29x\" through the points (\"0\",\"0\") and (\"-6\",\"4\")\r
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\n" ); document.write( "\n" ); document.write( "Notice how the two points lie on the line. This graphically verifies our answer.\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"-2%2F3\", you can find the perpendicular slope by this formula:
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\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%28-2%2F3%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%283%2F-2%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=3%2F2\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"3%2F2\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"3%2F2\" (its the negative reciprocal of \"-2%2F3\" from the line \"y=%28-2%2F3%29%2Ax%2B0\").\n" ); document.write( "Also since the unknown line goes through (-6,4), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-4=%283%2F2%29%2A%28x%2B6%29\" Plug in \"m=3%2F2\", \"x%5B1%5D=-6\", and \"y%5B1%5D=4\"
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\n" ); document.write( " \"y-4=%283%2F2%29%2Ax-%283%2F2%29%28-6%29\" Distribute \"3%2F2\"
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\n" ); document.write( " \"y-4=%283%2F2%29%2Ax%2B18%2F2\" Multiply
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\n" ); document.write( " \"y=%283%2F2%29%2Ax%2B18%2F2%2B4\"Add \"4\" to both sides to isolate y
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\n" ); document.write( " \"y=%283%2F2%29%2Ax%2B18%2F2%2B8%2F2\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%283%2F2%29%2Ax%2B26%2F2\" Combine the fractions
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\n" ); document.write( " \"y=%283%2F2%29%2Ax%2B13\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%28-2%2F3%29%2Ax%2B0\" and goes through (\"-6\",\"4\") is \"y=%283%2F2%29%2Ax%2B13\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%28-2%2F3%29%2Ax%2B0\" and \"y=%283%2F2%29%2Ax%2B13\"
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\n" ); document.write( "
\n" ); document.write( " graph of the given equation \"y=%28-2%2F3%29%2Ax%2B0\" (red) and graph of the line \"y=%283%2F2%29%2Ax%2B13\"(green) that is perpendicular to the given graph and goes through (\"-6\",\"4\")
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\n" ); document.write( "\n" ); document.write( "#3\r
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\n" ); document.write( "\n" ); document.write( "\"Write the equation for the line perpendicular to
\n" ); document.write( "2x - 5y = 5 and passes through the point (-2, -5).
\n" ); document.write( "Enter the variable expression Ax + By separately from the constant term C.
\n" ); document.write( "Your response should be given in standard form where A, B and C are the smallest possible integers and A > 0.\r
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\n" ); document.write( "\n" ); document.write( "First convert 2x - 5y = 5 to slope intercept form\r
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"2x-5y=5\" Start with the given equation


\"2x-5y-2x=5-2x\" Subtract 2x from both sides


\"-5y=-2x%2B5\" Simplify


\"%28-5y%29%2F%28-5%29=%28-2x%2B5%29%2F%28-5%29\" Divide both sides by -5 to isolate y


\"y+=+%28-2x%29%2F%28-5%29%2B%285%29%2F%28-5%29\" Break up the fraction on the right hand side


\"y+=+%282%2F5%29x-1\" Reduce and simplify


The original equation \"2x-5y=5\" (standard form) is equivalent to \"y+=+%282%2F5%29x-1\" (slope-intercept form)


The equation \"y+=+%282%2F5%29x-1\" is in the form \"y=mx%2Bb\" where \"m=2%2F5\" is the slope and \"b=-1\" is the y intercept.



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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"2%2F5\", you can find the perpendicular slope by this formula:
\n" ); document.write( "
\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"m%5Bp%5D=-1%2F%282%2F5%29\" So plug in the given slope to find the perpendicular slope
\n" ); document.write( "
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\n" ); document.write( "
\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%285%2F2%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"m%5Bp%5D=-5%2F2\" Multiply the fractions.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the perpendicular slope is \"-5%2F2\"
\n" ); document.write( "
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\n" ); document.write( "
\n" ); document.write( " So now we know the slope of the unknown line is \"-5%2F2\" (its the negative reciprocal of \"2%2F5\" from the line \"y=%282%2F5%29%2Ax-1\").\n" ); document.write( "Also since the unknown line goes through (-2,-5), we can find the equation by plugging in this info into the point-slope formula
\n" ); document.write( "
\n" ); document.write( " Point-Slope Formula:
\n" ); document.write( "
\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( "
\n" ); document.write( " \"y%2B5=%28-5%2F2%29%2A%28x%2B2%29\" Plug in \"m=-5%2F2\", \"x%5B1%5D=-2\", and \"y%5B1%5D=-5\"
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\n" ); document.write( " \"y%2B5=%28-5%2F2%29%2Ax%2B%285%2F2%29%28-2%29\" Distribute \"-5%2F2\"
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\n" ); document.write( " \"y%2B5=%28-5%2F2%29%2Ax-10%2F2\" Multiply
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\n" ); document.write( " \"y=%28-5%2F2%29%2Ax-10%2F2-5\"Subtract \"-5\" from both sides to isolate y
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\n" ); document.write( " \"y=%28-5%2F2%29%2Ax-10%2F2-10%2F2\" Make into equivalent fractions with equal denominators
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=%28-5%2F2%29%2Ax-20%2F2\" Combine the fractions
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\n" ); document.write( "
\n" ); document.write( " \"y=%28-5%2F2%29%2Ax-10\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%282%2F5%29%2Ax-1\" and goes through (\"-2\",\"-5\") is \"y=%28-5%2F2%29%2Ax-10\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%282%2F5%29%2Ax-1\" and \"y=%28-5%2F2%29%2Ax-10\"
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\n" ); document.write( " graph of the given equation \"y=%282%2F5%29%2Ax-1\" (red) and graph of the line \"y=%28-5%2F2%29%2Ax-10\"(green) that is perpendicular to the given graph and goes through (\"-2\",\"-5\")
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\n" ); document.write( "\n" ); document.write( "Now convert \"%28-5%2F2%29x-10\" back to standard form\r
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from slope-intercept form (y = mx+b) to standard form (Ax+By = C)


\"y+=+%28-5%2F2%29x-10\" Start with the given equation


\"2%2Ay+=+2%2A%28%28-5%2F2%29x-10%29\" Multiply both sides by the LCD 2


\"2y+=+-5x-20\" Distribute and multiply


\"2y%2B5x+=+-5x-20%2B5x\" Add 5x to both sides


\"5x%2B2y+=+-20\" Simplify


The original equation \"y+=+%28-5%2F2%29x-10\" (slope-intercept form) is equivalent to \"5x%2B2y+=+-20\" (standard form where A > 0)


The equation \"5x%2B2y+=+-20\" is in the form \"Ax%2BBy+=+C\" where \"A+=+5\", \"B+=+2\" and \"C+=+-20\"



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\n" ); document.write( "\n" ); document.write( "If you have any further questions, feel free to ask.
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