document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101648>Question 1101648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation below as one involving only sin&#952; and cos&#952;. \r<BR>\n" );
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document.write( "sin2&#952;+cos&#952; \r<BR>\n" );
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document.write( "It's not supposed to equal anything, that's how it is on my homework. I don't understand how to do this and am overall confused with trig addition and subtraction. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716255 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716255\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Make it sin and cos of t, not of 2t.<BR>\n" );
document.write( "sin(2t) = 2sin(t)*cos(t)<BR>\n" );
document.write( "--> 2sin(t)*cos(t) + cos(t)<BR>\n" );
document.write( "That's all. </SPAN>\n" );
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