document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101644>Question 1101644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you substitution 5x+6y=-18 and y=6x-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716247 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use y=6x-3 for y in the first equation.<BR>\n" );
document.write( "It becomes 5x+6(6x-3)=-18<BR>\n" );
document.write( "That is 5x+36x-18=-18 by distributing the 6<BR>\n" );
document.write( "41x=0<BR>\n" );
document.write( "x=0<BR>\n" );
document.write( "y=-3<BR>\n" );
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