document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=157616>Question 157616</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 3pm a plane leaves London to fly to Madrid which is 1260 miles away.  At 4PM a plane leaves Madrid to fly to London.  The second plane flies 40 MPH faster than the first plane.  If the planes pass one another at 4:30pm, what is the speed of each plane? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716185 by </B><A HREF=/tutors/aboutme.mpl?userid=amalm06><B>amalm06(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amalm06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amalm06><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note that the total distance flown by both planes when they meet is 1260 mi. Therefore, one plane flies x mi, while the other plane flies 1260-x mi.<BR>\n" );
document.write( "Using d=rt, where d refers to the distance traveled along one dimension, and r refers to the average speed, we have the following system of equations:\r<BR>\n" );
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document.write( "x=1.5r\r<BR>\n" );
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document.write( "1260-x=0.5(r+40)\r<BR>\n" );
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document.write( "Solve for r:\r<BR>\n" );
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document.write( "1.5r=1240-0.5r\r<BR>\n" );
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document.write( "3r=1240\r<BR>\n" );
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document.write( "r=620 mph (Answer), r=660 mph (Answer)  </SPAN>\n" );
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