document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98445>Question 98445</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321233832/algebrahomeworkh>elementary and intermediate algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> the sum ot three numbers is 105. the third is 11 less than ten times the second. twice the first is 7 more than three times the second. find the numbers.\r<BR>\n" );
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document.write( "my work so far:\r<BR>\n" );
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document.write( "a+b+c=105<BR>\n" );
document.write( "10b=c+11  >>  10b-c=1<BR>\n" );
document.write( "2a=7+3b   >>  2a-3b=7\r<BR>\n" );
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document.write( "next i know i have to get rid of one of the numbers so i decided on \"a\" and i started with equations 1 and 3 so i multiplyed 1 by 2 so the \"a\"s would cancel out.\r<BR>\n" );
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document.write( "-2a-2b-c=105<BR>\n" );
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document.write( "2a-3b=7\r<BR>\n" );
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document.write( "-5b-c=112\r<BR>\n" );
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document.write( "but now im stuck i dont know what to do next.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71613 by </B><A HREF=/tutors/aboutme.mpl?userid=mathslover><B>mathslover(157)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathslover><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathslover><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71613\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the second number be x<BR>\n" );
document.write( "from the problem statement \"the third is 11 less than ten times the second\"<BR>\n" );
document.write( "third number = 10x -11<BR>\n" );
document.write( "again from the problem statement \"first is 7 more than three times the second\"<BR>\n" );
document.write( "first number = 3x + 7 \r<BR>\n" );
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document.write( "Sum of the numbers  =105\r<BR>\n" );
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document.write( "3x+7 + x + 10x-11 =105<BR>\n" );
document.write( "14x = 109 <BR>\n" );
document.write( "x= 109/14\r<BR>\n" );
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document.write( "second number is 109/14<BR>\n" );
document.write( "first number = 10* 109/14 -11<BR>\n" );
document.write( "             =936/14\r<BR>\n" );
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document.write( "third number = 3* 109/14 + 7<BR>\n" );
document.write( "             =425/14  </SPAN>\n" );
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