document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101520>Question 1101520</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I found  the hypotenuse of sqrt of 8^2+10^2= sqrt 164=12.81, my question is how did I get 12.81 from the sqrt of 64? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716120 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You just said that YOU found the hypotenuse. How could we know what YOU did?\r<BR>\n" );
document.write( "\n" );
document.write( "At any rate sqrt 164=12.8062484749=12.81<BR>\n" );
document.write( "It is sqrt of 164 NOT sqrt of 64<BR>\n" );
document.write( "164 not 64 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );