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document.write( "If we assume x and y are positive, then we can draw \r\n" );
document.write( "a couple of right triangles, one containing acute angle\r\n" );
document.write( "A and one containing acute angle B.\r\n" );
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document.write( "A is the angle whose sine is x, or x/1, so since the sine is the\r\n" );
document.write( "opposite over the hypotenuse we put x on the opposite side of A\r\n" );
document.write( "and 1 on the hypotenuse, then use the Pythagorean theorem to calculate\r\n" );
document.write( "the adjacent side.\r\n" );
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document.write( "B is the angle whose tangent is y, or y/1, so since the tangent is the\r\n" );
document.write( "opposite over the adjacent we put y on the opposite side of B\r\n" );
document.write( "and 1 on the adjacent side, then use the Pythagorean theorem to calculate\r\n" );
document.write( "the hypotenuse. \r\n" );
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document.write( "So \r\n" );
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document.write( "Warning: This solution assumes that x and y are both positive,\r\n" );
document.write( "which puts the angles A and B both in quadrant I. \r\n" );
document.write( "If x and/or y were negative then A and/or B could be in other \r\n" );
document.write( "quadrants, which would cause one or both of the terms in the\r\n" );
document.write( "numerator to have negative signs.\r\n" );
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document.write( "Edwin
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