document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101497>Question 1101497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The probabilities that two students will not show up for class on a beautiful spring day are 0.3 and 0.4, respectively. It is a beautiful spring day. Find the following probabilities. (See Example 6. Round your answers to two decimal places.)\r<BR>\n" );
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document.write( "(a) Neither will show up for class.<BR>\n" );
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document.write( "(b) Both will show up for class.<BR>\n" );
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document.write( "(c) Exactly one will show up for class.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716096 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The given information is<BR>\n" );
document.write( "P(A does not show up) = 0.3<BR>\n" );
document.write( "P(B does not show up) = 0.4<br><BR>\n" );
document.write( "We then know that<BR>\n" );
document.write( "P(A shows up) = 1-0.3 = 0.7<BR>\n" );
document.write( "P(B shows up) = 1-0.4 = 0.6<br><BR>\n" );
document.write( "Then<br><BR>\n" );
document.write( "(a) P(neither shows up) = P((A does not show up) AND (B does not show up)) = (0.3)(0.4) = 0.12<BR>\n" );
document.write( "(b) P(both show up) = P((A shows up) AND (B shows up)) = (0.7)(0.6) = 0.42<BR>\n" );
document.write( "(c) p(exactly one shows up) = P(((A shows up) AND (B does not)) OR ((B shows up) AND (A does not))) = (0.7)(0.4)+(0.6)(0.3) = 0.28 + 0.18 = 0.46<br><BR>\n" );
document.write( "Note that the three cases together cover all the possibilities; so a good check of your answers is to show that the sum of the probabilities is 1:<br><BR>\n" );
document.write( "0.12 + 0.42 + 0.46 = 1.00<BR>\n" );
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