document.write( "Question 1101445: Keisha takes out a loan for her college tuition from a bank that charges simple interest at an annual rate of 8.95%. Her loan is for 3500 for 11 months. assume each month is 1/12 of a year..\r
\n" ); document.write( "\n" ); document.write( "Find the interest that will be owed after 11 months \r
\n" ); document.write( "\n" ); document.write( "Assuming Keisha doesn’t make any payments,find the amount owed after11 months...\r
\n" ); document.write( "\n" ); document.write( "The part that has me baffled is assume each month is 1/12 of a year ....
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Algebra.Com's Answer #716058 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Keisha takes out a loan for her college tuition from a bank that charges simple interest at an annual rate of 8.95%. Her loan is for 3500 for 11 months. assume each month is 1/12 of a year..
\n" ); document.write( "Find the interest that will be owed after 11 months
\n" ); document.write( "Assuming Keisha doesn’t make any payments,find the amount owed after11 months...
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\n" ); document.write( "I = P*r*t
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\n" ); document.write( "I = 3500*0.0895*(11/12) = $287.15
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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