document.write( "Question 1101445: Keisha takes out a loan for her college tuition from a bank that charges simple interest at an annual rate of 8.95%. Her loan is for 3500 for 11 months. assume each month is 1/12 of a year..\r
\n" );
document.write( "\n" );
document.write( "Find the interest that will be owed after 11 months \r
\n" );
document.write( "\n" );
document.write( "Assuming Keisha doesn’t make any payments,find the amount owed after11 months...\r
\n" );
document.write( "\n" );
document.write( "The part that has me baffled is assume each month is 1/12 of a year .... \n" );
document.write( "
Algebra.Com's Answer #716058 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Keisha takes out a loan for her college tuition from a bank that charges simple interest at an annual rate of 8.95%. Her loan is for 3500 for 11 months. assume each month is 1/12 of a year.. \n" ); document.write( "Find the interest that will be owed after 11 months \n" ); document.write( "Assuming Keisha doesn’t make any payments,find the amount owed after11 months... \n" ); document.write( "---- \n" ); document.write( "I = P*r*t \n" ); document.write( "----- \n" ); document.write( "I = 3500*0.0895*(11/12) = $287.15 \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " \n" ); document.write( " |