document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101404>Question 1101404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the sequence: 5,14,23,32,..., determine the 56th term and the sum of the first 57 terms. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716023 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716023\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is an arithmetic sequence with common difference = 9 and 1st term = 5<BR>\n" );
document.write( "The nth term is a_n = a1 + (n-1)*d <BR>\n" );
document.write( "Thus a_n = 5 + 9(n-1) = 9n - 4<BR>\n" );
document.write( "Therefore a_56 = 9*56 - 4 = 500<BR>\n" );
document.write( "The sum of the 1st n terms is given by S(n) = (n/2)(a1 + an)<BR>\n" );
document.write( "a_57 = 9 + a_56 = 509<BR>\n" );
document.write( "S(57) = (57/2)(5 + 509) = 14649 </SPAN>\n" );
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