document.write( "Question 98190: Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y^3-13y^2+54y-72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height? \n" ); document.write( "
Algebra.Com's Answer #71602 by ankor@dixie-net.com(22740)\"\" \"About 
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Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y^3-13y^2+54y-72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height?
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\n" ); document.write( "Divide (y-6) into y^3 - 13y^2 + 54y - 72 using synthetic division:
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\n" ); document.write( " 6 |1 - 13 + 54 - 72
\n" ); document.write( ".....0 + 6 - 42 + 72
\n" ); document.write( "....------------------
\n" ); document.write( ".....1 - 7 + 12 + 0
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\n" ); document.write( "This gives us a quotient of:
\n" ); document.write( " y^2 - 7y + 12
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\n" ); document.write( "Which factors to:
\n" ); document.write( "(y - 3)(y - 4); the new height and length
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\n" ); document.write( "you can check solution by (y-6)*(y-3)*(y-4)
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