document.write( "Question 98428: A manager sell peanuts for $2.50 per pound. He wants to mix cashews that sell for $5.00 a pound with the peanuts to create 30 pounds of a mixture that sells for $4.00 a pound. How many pounds of each nut are needed.
\n" ); document.write( "please show me how to set this up and solve it
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Algebra.Com's Answer #71600 by Earlsdon(6294)\"\" \"About 
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Well, you can start by assigning variables to the unknown quantities.
\n" ); document.write( "Let P = the number of pounds of peanuts at $2.50 per pound.
\n" ); document.write( "Let C = the number of pounds of cashews at $5.00 per pound.
\n" ); document.write( "From the problem description, you are told that P + C = 30 pounds and this mixture will cost $4.00 per pound.
\n" ); document.write( "We have enough information to set up the necessary equation, but there are two unknowns and only one equation. We need to reduce the number of unknowns to only one.
\n" ); document.write( "$2.50(P) + $5.00(C) = $4.00(30) but you are also told that:
\n" ); document.write( "P + C = 30 which can be written as C = 30 -P so we'll replace the C with 30-P.
\n" ); document.write( "$2.50(P) + $5.00(30-p) = $4.00(30) Now you can simplify this and solve for P.
\n" ); document.write( "2.5P+5(30-P) = 4(30)
\n" ); document.write( "2.5P+150-5P = 120 Combining like-terms, we get:
\n" ); document.write( "-2.5P = -30 Divide both sides by -2.5
\n" ); document.write( "P = 12 You will need 12 pounds of peanuts.
\n" ); document.write( "C = 30-P
\n" ); document.write( "C = 30-12
\n" ); document.write( "C = 18 You will need 18 pounds of cashews.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "Cost of 12 pounds of peanuts + cost of 18 pounds of cashews = cost 0f 30 pounds of mixed nuts at $4.00 per pound.
\n" ); document.write( "$2.50(12) + $5.00(18) = $4.00(30)
\n" ); document.write( "$30.00 + $90.00 = $120
\n" ); document.write( "$120.00 = $120.00
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