document.write( "Question 1101380: the distance between towns m and m is 280km, a car and a lorry can travel from m to n. the average speed for the lorry 20km/hr less than that of the car. the lorry takes 1 hr 10 min more than the car to travel from m to n.
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document.write( "a) if the speed of the lorry is x km/hr , find x?
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document.write( "b) the lorry left town m at 8:15am . the car left town m later and overtook the lorry at 12:15pm. calculate the time the car left town m.
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Algebra.Com's Answer #715973 by josgarithmetic(39628) ![]() You can put this solution on YOUR website! If you only look at part (a), \n" ); document.write( "(Doing for speed of the car; not the lorry)\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "CAR r t 280\r\n" ); document.write( "LORRY r-20 t+1&1/6 280\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "and using the given time difference, \n" ); document.write( " \r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "CAR r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for r to get the car's speed: \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "if no mistakes in algebra steps done on paper, then \n" ); document.write( "r for the Car,\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |