document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1100445>Question 1100445</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if A has a magnitude of 55.9 an B has a magnitude of 42.3 find the magnitude R of the resultant and the angle that resultant makes with vector B given the angle with A is 55.5 degrees  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #715968 by </B><A HREF=/tutors/aboutme.mpl?userid=jimbols><B>jimbols(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jimbols><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=715968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can use force triangle in this situation. \r<BR>\n" );
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document.write( "Using Cosine Law,<BR>\n" );
document.write( "  R² = 55.9² + 42.3² - 2(55.9)(42.3)cos(124.5)<BR>\n" );
document.write( "  R = 87.14\r<BR>\n" );
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document.write( "Using Sine Law,<BR>\n" );
document.write( "  87.14/sin(124.5) = 55.9/sin(&#415;)<BR>\n" );
document.write( "  &#415;; = 31.916 degrees </SPAN>\n" );
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