document.write( "Question 1101300: iceman has enclosed one of his mortal enemies in a cube of ice. it is melting uniformly with the volume decreasing by 3 cubic feet per sec how fast is the surface area decreasing when the cubes edge is 5 ft?
\n" ); document.write( "
\n" ); document.write( "i got lost when they are asking about the surface area. Thanks for helping out!
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #715962 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
AS A CALCULUS PROBLEM:
\n" ); document.write( "\"E\"= length of the edge, in ft
\n" ); document.write( "\"A=6s%5E2\"= surface area of the cube, in square feet
\n" ); document.write( "\"V=s%5E3\"= volume of the cube, in cubic feet
\n" ); document.write( "\"t\"= time, in seconds
\n" ); document.write( "\"E\" , \"A\" , and \"V\" are functions of \"t\" .
\n" ); document.write( "We know the rate of change of \"V\" with \"t\" , \"dV%2Fdt\" .
\n" ); document.write( "If we figure out the relations among the derivatives of those functions,
\n" ); document.write( "we can calculate the rate of change for \"A\" and \"E\" .
\n" ); document.write( "\"dA%2Fdt=6%2A2E%2A%28dE%2Fdt%29=12E%2A%28dE%2Fdt%29\"
\n" ); document.write( "\"dV%2Fdt=3E%5E2%2A%28dE%2Fdt%29=-3\"
\n" ); document.write( "If \"3E%5E2%2A%28dE%2Fdt%29=-3\" , then \"dE%2Fdt=-1%2FE%5E2\"
\n" ); document.write( "Substituting that into the expression for \"dA%2Fdt\" ,
\n" ); document.write( "\"dA%2Fdt=12E%2A%28dE%2Fdt%29=12E%2A%28-1%2FE%5E2%29=-12%2FE\"
\n" ); document.write( "When \"E=5\" , \"dA%2Fdt=-12%2F5=-2.4\" .
\n" ); document.write( "When the cube's edge is 5 ft,
\n" ); document.write( "the surface area is decreasing at a rate of
\n" ); document.write( "\"highlight%282.4%29\" square feet per second.
\n" ); document.write( "
\n" ); document.write( "OTHER OPTIONS:
\n" ); document.write( "As a good approximation, calculate the average rate of area decrease
\n" ); document.write( "between 0.01 seconds before the cube edge measures 5 ft
\n" ); document.write( "and 0.01 seconds after the cube edge measures 5 ft.
\n" ); document.write( "When the edge measures 5 ft, the volume, in cubic feet, is
\n" ); document.write( "\"5%5E3=125\" .
\n" ); document.write( "0.01 seconds before that, the volume, in cubic feet, is
\n" ); document.write( "\"125%2B0.01%2A3=125.03\" ,
\n" ); document.write( "the edge length, in feet, is \"root%283%2C125.03%29=5.0004\" ,
\n" ); document.write( "and the surface area, in square feet, is
\n" ); document.write( "\"6%2A5.0004%5E2=150.024\" .
\n" ); document.write( "0.01 seconds after the edge measures 5 ft, the volume, in cubic feet, is
\n" ); document.write( "\"125-0.01%2A3=124.97\" ,
\n" ); document.write( "the edge length, in feet, is \"root%283%2C124.97%29=4.9996\" ,
\n" ); document.write( "and the surface area, in square feet, is
\n" ); document.write( "\"6%2A4.9996%5E2=149.976\" .
\n" ); document.write( "So, over the course of 0.02 seconds,
\n" ); document.write( "the surface area decrease, in square feet, is
\n" ); document.write( "\"150.024-149.976=0.048\" ,
\n" ); document.write( "making the rate of decrease, in square feet per second,
\n" ); document.write( "\"0.048%2F0.02=2.4\" .
\n" ); document.write( "
\n" );