document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101338>Question 1101338</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has an area of 2340 sq.cm.. When the length and width are both increased by 2 cm each, the area is increased by 206 sq. cm. Find the original perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #715924 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=715924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let l and w be the width and length of the rectangle, respectively. Then:<BR>\n" );
document.write( "lw=2340 and<BR>\n" );
document.write( "(l+2)(w+2)=2340+206=2546<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "l=2340/w<BR>\n" );
document.write( "(2340/w +2)(w+2)=2546<BR>\n" );
document.write( "2340+4680/w+2w+4=2546<BR>\n" );
document.write( "4680/w+2w=202<BR>\n" );
document.write( "4680+2w²=202w<BR>\n" );
document.write( "2w²-202w+4680=0<BR>\n" );
document.write( "w²-101w+2340=0<BR>\n" );
document.write( "(w-65)(w-36)=0<BR>\n" );
document.write( "w=65 or 36<BR>\n" );
document.write( "The width is 36; and the length is 65, making the original perimeter 202cm<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786;<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );