document.write( "Question 1101338: A rectangle has an area of 2340 sq.cm.. When the length and width are both increased by 2 cm each, the area is increased by 206 sq. cm. Find the original perimeter. \n" ); document.write( "
Algebra.Com's Answer #715922 by josgarithmetic(39617)\"\" \"About 
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Rectangle dimensions x and y\r
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\n" ); document.write( "\n" ); document.write( "\"xy=2340\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%28y%2B2%29-xy=206\"\r
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\n" ); document.write( "\n" ); document.write( "\"xy%2B2y%2B2x%2B4-xy=206\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B2y%2B4=206\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2By%2B2=103\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=101\"\r
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\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=101%2Cxy=2340\"-----either factorize 2340 and look for combinations that work, or substitute and solve a quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28101-x%29=2340\"\r
\n" ); document.write( "\n" ); document.write( "\"101x-x%5E2-2340\"\r
\n" ); document.write( "\n" ); document.write( "\"-x%5E2%2B101x-2340=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-101x%2B2340=0\"\r
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\n" ); document.write( "\n" ); document.write( "discriminant, \"101%5E2-4%2A2340=841=29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=%28101%2B-+29%29%2F2%29\"-------------one of these will be 'x' and the other is y.\r
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\n" ); document.write( "\n" ); document.write( "Dimensions: 36 and 65
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