document.write( "Question 1101289: The count in a culture of bacteria was 200 after 2 hours and 25000 after 5 hours.
\n" ); document.write( "a. Find a function that models the number of bacteria n(t) after t hours.
\n" ); document.write( "b. When does the culture contain 2,000 bacteria?\r
\n" ); document.write( "\n" ); document.write( "I am taking an online pre-calc math class. Our math teacher does not make videos for us but I have a text book. However, I feel like the text book does not have enough examples for us and I need help on this problem. I would appreciate to see the work so I can understand the problem. Thank you!
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Algebra.Com's Answer #715895 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The number of bacteria is increasing exponentially, so the function is of the form
\n" ); document.write( "\"y+=+ab%5Ex\"
\n" ); document.write( "where a is an initial value (when x=0) and b is the growth rate.

\n" ); document.write( "(1) Use the two given pieces of information to write equations in that form, using x as the time in hours:
\n" ); document.write( "\"200+=+ab%5E2\"
\n" ); document.write( "\"25000+=+ab%5E5\"

\n" ); document.write( "(2) Divide the second equation by the first; that will eliminate a, allowing you to find the value of b:
\n" ); document.write( "\"125+=+b%5E3\"
\n" ); document.write( "\"5+=+b\"

\n" ); document.write( "Remember not to just go through the motions of solving the problem; take the time to realize that b=5 means the number of bacteria grows by a factor of 5 each hour.
\n" ); document.write( "(You will appreciate the mathematics more if you understand what it is doing....)

\n" ); document.write( "(3) Use the value you have found for b in either of the original equations to find the value of a:
\n" ); document.write( "\"200+=+a%285%29%5E2\"
\n" ); document.write( "\"200+=+25a\"
\n" ); document.write( "\"a+=+8\"

\n" ); document.write( "So the function is \"y+=+8%285%29%5Ex\"

\n" ); document.write( "For part b, you need to solve the equation \"8%285%29%5Ex+=+2000\"

\n" ); document.write( "Up to now, the numbers have worked out nicely; a and b are whole numbers. That will no longer be the case:
\n" ); document.write( "f(0) = 8
\n" ); document.write( "f(1) = 40
\n" ); document.write( "f(2) = 200
\n" ); document.write( "f(3) = 1000
\n" ); document.write( "f(4) = 5000
\n" ); document.write( "f(5) = 25000
\n" ); document.write( "So the solution to part b will be between 3 and 4 hours.

\n" ); document.write( "To solve algebraically, because the variable is in an exponent, you need to use logarithms.

\n" ); document.write( "\"8%285%5Ex%29+=+2000\"
\n" ); document.write( "\"5%5Ex+=+250\"
\n" ); document.write( "\"x%2Alog%285%29+=+log%28250%29\"
\n" ); document.write( "\"x+=+log%28250%29%2Flog%285%29+=+3.43\" (to 2 decimal places)
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