Algebra.Com's Answer #715870 by ikleyn(52798)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "Ben drove to Kate’s house. It took 30 mins. On the trip back to her own house, Ben drove an average of 15 mph slower
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document.write( "than the trip to Kate’s house and it took an extra 15 mins. How far is it from Ben’s house to Kate’s house?
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document.write( "Is Ben \"he\" or \"she\" ?\r
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document.write( "Comment from student: Sorry, Ben is a he.
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document.write( "My response: OK.\r
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document.write( "The way to Katy took 30 minutes =  of an hour.\r\n" );
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document.write( "The way back took 45 minutes =  of an hour.\r\n" );
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document.write( "The \"distance equation\", saying that both ways distance is the same is\r\n" );
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document.write( " =  , where \"v\" is the average speed on the way \"to there\".\r\n" );
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document.write( "Multiply both sides by 4. You will get\r\n" );
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document.write( "2v = 3*(v-15) ====>\r\n" );
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document.write( "2v = 3v - 45 ====> v = 45.\r\n" );
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document.write( "Then one way distance is =  = 22.5 miles.\r\n" );
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document.write( "Check. The way \"to there\"  = of an hour.\r\n" );
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document.write( " The way back  =  = of an hour. ! Correct !\r\n" );
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document.write( "Answer. One way distance is 22.5 miles.\r\n" );
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