document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=830185>Question 830185</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have 100 gallons of 70% solution. I need to mix it with a 90% solution to obtain a 75% solution. How much 90% do I need? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #715849 by </B><A HREF=/tutors/aboutme.mpl?userid=amalm06><B>amalm06(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amalm06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amalm06><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=715849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A denote the 70% solution and B denote the 90% solution\r<BR>\n" );
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document.write( "Using the method of alligation,\r<BR>\n" );
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document.write( "0.75-0.70=0.05\r<BR>\n" );
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document.write( "0.90-0.75=0.15\r<BR>\n" );
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document.write( "So that A/B=0.15/0.05\r<BR>\n" );
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document.write( "E.g. there are 0.15 parts of A for every 0.05 parts of B\r<BR>\n" );
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document.write( "If there are 100 parts of A, then (0.15/0.05)=100/x\r<BR>\n" );
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document.write( "x=33.3 gallons of 90% solution (Answer)  </SPAN>\n" );
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