document.write( "Question 1101272: As an incentive to do homework, Professor Rouse randomly draws three students' names, and they are expected to explain a homework problem of the day. On a particular day, 7 students have not done homework and 24 have. Find the following probabilities.\r
\n" ); document.write( "\n" ); document.write( "(a) The first two drawn have not done homework and the third has
\n" ); document.write( "(b) All three drawn have not done homework.
\n" ); document.write( "(c) All three drawn have done homework
\n" ); document.write( "(d) At least one of the three drawn has done homework.
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Algebra.Com's Answer #715812 by Boreal(15235)\"\" \"About 
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a. (7/31)(6/30)(24/29)=0.0374
\n" ); document.write( "b. (7/31)(6/30)(5/29)=0.0078
\n" ); document.write( "c.(24/31)(23/30)(22/29)=0.4503
\n" ); document.write( "d. This is 1-c or 0.9922, because at least one of the three is 1-(p that none did)
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