document.write( "Question 1101216: A metal recycling plant has some scrap metal that is 41% copper. It also has some other scrap metal that is 5% copper. The scrap metal is melted together and produces 1700 g of metal that is 44% copper. How many grams of the 51% copper metal were mixed with the 41% copper metal?\r
\n" ); document.write( "\n" ); document.write( "A.1190 g
\n" ); document.write( "B.510 g
\n" ); document.write( "C.867 g
\n" ); document.write( "D.1700 g
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Algebra.Com's Answer #715782 by greenestamps(13206)\"\" \"About 
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\n" ); document.write( "You can solve mixture problems like this quickly using the method of alligation.

\n" ); document.write( "Do a search of the internet if you want to learn about the method; I will just give you a quick description of how your example is solved using the method.

\n" ); document.write( "The percentages of copper in the two ingredients in the mixture are 41 and 51; the percentage in the mixture is 44.

\n" ); document.write( "The 44 is 3/10 of the way from 41 to 51 (from 41 to 51 is 10; from 41 to 44 is 3).

\n" ); document.write( "That means 3/10 of the mixture is the 51% copper scrap metal.

\n" ); document.write( "3/10 of 1700g is 510g.

\n" ); document.write( "Answer B
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