document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101215>Question 1101215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Kang mixes an 85% sugar cinnamon-flavored solution with a 75% sugar cherry-flavored solution to make 20 gallons of a new product. The new product is 76% sugar. How much of the cherry-flavored solution did he use?\r<BR>\n" );
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document.write( "A.15 gal<BR>\n" );
document.write( "B.2 gal<BR>\n" );
document.write( "C.18 gal<BR>\n" );
document.write( "D.20 gal </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #715779 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13215)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=715779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The other tutor provided a solution using a variation of the standard algebraic method for solving \"mixture\" problems.<br><BR>\n" );
document.write( "There is a much easier method you can use, if you understand it.<br><BR>\n" );
document.write( "Think of the percentages of the two ingredients and the final mixture on a number line: 75, 76, and 85.<br><BR>\n" );
document.write( "The mixture percentage 76 is 1/10 of the distance from 75 to 85.  (From 75 to 85 is 10; from 75 to 76 is 1.)<br><BR>\n" );
document.write( "That means 1/10 of the mixture must be the 85% ingredient.  With a total of 20 gallons of the mixture, that means 2 gallons.<br><BR>\n" );
document.write( "Answer: use 2 gallons of the 85% sugar cinnamon-flavored solution and 18 gallons of the 75% sugar cherry flavored solution. </SPAN>\n" );
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