document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101180>Question 1101180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The population of a town increased by 16 2/3 % in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #715778 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=715778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The other tutor's answer is not right; you should be able to see where he made his arithmetic error.<br><BR>\n" );
document.write( "16 2/3% as a fraction is 1/6; so the population of the town increased by 1/6 in 1990.  Since the population at the beginning of 1990 was 30,000, it increase by 5,000 during 1990, making the population at the beginning of 1991 35,000.<br><BR>\n" );
document.write( "10% as a fraction is 1/10; so in 1991 the population increased by 1/10 of 35,000, or 3,500, making the population at the end of 1991 38,500. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );