document.write( "Question 1101180: The population of a town increased by 16 2/3 % in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991? \n" ); document.write( "
Algebra.Com's Answer #715769 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! corrected \n" ); document.write( "16 2/3=50/3 \n" ); document.write( "16 2/3%=50/300 \n" ); document.write( "350/300=116 2/3%=1.16 2/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(350/300)*1.1*30000=38500 \n" ); document.write( " |