document.write( "Question 1101180: The population of a town increased by 16 2/3 % in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991? \n" ); document.write( "
Algebra.Com's Answer #715769 by richwmiller(17219)\"\" \"About 
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corrected
\n" ); document.write( "16 2/3=50/3
\n" ); document.write( "16 2/3%=50/300
\n" ); document.write( "350/300=116 2/3%=1.16 2/3\r
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\n" ); document.write( "\n" ); document.write( "(350/300)*1.1*30000=38500
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