document.write( "Question 1101216: A metal recycling plant has some scrap metal that is 41% copper. It also has some other scrap metal that is 5% copper. The scrap metal is melted together and produces 1700 g of metal that is 44% copper. How many grams of the 51% copper metal were mixed with the 41% copper metal?\r
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document.write( "A.1190 g
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document.write( "B.510 g
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document.write( "C.867 g
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document.write( "D.1700 g \n" );
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Algebra.Com's Answer #715760 by richwmiller(17219) You can put this solution on YOUR website! We know the total amount is 1700 g \n" ); document.write( "We know the percentage of the total amount is 44% \n" ); document.write( "We know the total amount has 748 g of 100% \n" ); document.write( "We want to know the amount of copper at 41% \n" ); document.write( "We want to know the amount of copper at 51% \n" ); document.write( "x+y=1700, \n" ); document.write( "0.41*x+0.51*y=0.44*1700 \n" ); document.write( "0.41*x+0.51*y=748 \n" ); document.write( "x=1700-y \n" ); document.write( "0.41*(1700-y)+0.51*y=748 \n" ); document.write( "697-0.41y+0.51*y=748 \n" ); document.write( "0.1*y=51 \n" ); document.write( "We now know amount of copper at 51% \n" ); document.write( "y=510 g at 51% \n" ); document.write( "x=1700-y \n" ); document.write( "We now know amount of copper at 41% \n" ); document.write( "x=1190 g at 41% \n" ); document.write( "check \n" ); document.write( "0.41*1190+0.51*510=0.44*1700 \n" ); document.write( "487.9+260.1=748 \n" ); document.write( "748=748 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |