document.write( "Question 98404: Consider the line y= -7x+8. \r
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\n" ); document.write( "\n" ); document.write( "Find the equation of the line that is parallel to this line and passes through the point(5,9).
\n" ); document.write( "Find the equation of the line that is perpendicular to this line and passes through the point(5.9) .\r
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Algebra.Com's Answer #71573 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
Y=-7X+8 (RED LINE) HAS A SLOPE OF -7.
\n" ); document.write( "THUS A PARALLEL LINE THROUGH (5,9) WITH A SLOPE OF -7 IS:
\n" ); document.write( "9=-7*5+b
\n" ); document.write( "9=-35+b
\n" ); document.write( "b=9+35
\n" ); document.write( "b=44 FOR THE Y INTERCEPT.
\n" ); document.write( "THUS THIS LINE EQUATION IS:
\n" ); document.write( "Y=-7X+44 (GREEN LINE)
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+50%2C+y+=+-7x+%2B8%2C+y+=+-7x+%2B44%29+\" (graph 300x200 pixels, x from -6 to 5, y from -10 to 50, of TWO functions y = -7x +8 and y = -7x +44).
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\n" ); document.write( "A PERPENDICULAR LINE WILL HAVE A SLOPE OF 1/7 (THE NEGATIVE RECIPRICAL OF -7)
\n" ); document.write( "9=5/7+b
\n" ); document.write( "9-5/7=b
\n" ); document.write( "b=(63-5)/7
\n" ); document.write( "b=58/7 FOR THIS Y INTERCEPT.
\n" ); document.write( "Y=X/7+58/7 IS THIS LINE EQUATION (GREEN LINE)
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+-7x+%2B8%2C+y+=+x%2F7+%2B58%2F7%29+\" (graph 300x200 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = -7x +8 and y = x/7 +58/7).
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