document.write( "Question 1101146: A person bought a car for $21,049. After 3 years, the car was worth $11,980. If the value of the car continues to decrease exponentially at this rate, then determine the time it will take to be worth $5498 \n" ); document.write( "
Algebra.Com's Answer #715717 by josgarithmetic(39629)\"\" \"About 
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\"y=21049%2Ae%5E%28-k%2Ax%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"11980=21049%2Ae%5E%28-3k%29\"\r
\n" ); document.write( "\n" ); document.write( "\"11980%2F21049=e%5E%28-3k%29\"\r
\n" ); document.write( "\n" ); document.write( "\"0.569148=e%5E%28-3k%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-0.5636148=-3k\"\r
\n" ); document.write( "\n" ); document.write( "\"k=0.5636148%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"k=0.1879\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28y=21049%2Ae%5E%28-0.1879x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "When will \"y=5498\"?
\n" ); document.write( "\"21049%2Ae%5E%28-0.1879x%29=5498\"\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%28-0.1879x%29=0.261200\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28e%5E%28-0.1879x%29%29=-1.3425\"\r
\n" ); document.write( "\n" ); document.write( "\"-0.1879x=-1.3425\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28x=7.144%29\"\"years\"\r
\n" ); document.write( "\n" ); document.write( "Close to 7 years 8 weeks.\r
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