document.write( "Question 98406This question is from textbook beginning and intermediate algebra
\n" ); document.write( ": One roofer can put a neew roof on a house three times faster than another. Working together they can roof a house in 4 days. How long would it take the faster roofer working alone? I need to know how to set up the problem then i can work it from there \n" ); document.write( "
Algebra.Com's Answer #71570 by checkley71(8403)\"\" \"About 
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X*3X/(X+3X)=4 X= THE TIME FOR THE FASTER ROOFER.
\n" ); document.write( "3X^2/4X=4 NOW CROSS MULTIPLY
\n" ); document.write( "3X^2=16X
\n" ); document.write( "3X^2-16X=0
\n" ); document.write( "X(3X-16)=0
\n" ); document.write( "X=0 A NON ANSWER.
\n" ); document.write( "3X-16=0
\n" ); document.write( "3X=16
\n" ); document.write( "X=16/3 DAYS FOR THE FASTER ROOFER.
\n" ); document.write( "3*16/3=16 DAYS FOR THE SLOWER ROOFER.
\n" ); document.write( "PROOF
\n" ); document.write( "16/3*16/(16/3+16=4
\n" ); document.write( "(256/3)/[(16+16*3)/3]=4
\n" ); document.write( "(256/3)/[(16+48)/3]=4
\n" ); document.write( "(256/3)/(64/3)=4
\n" ); document.write( "NOW INVERT THE DENOMINATOR & MULTIPLY
\n" ); document.write( "(256/3)(3/64)=4 CANCEL OUT THE 3s.
\n" ); document.write( "256/64=4
\n" ); document.write( "4=4
\n" ); document.write( " \n" ); document.write( "
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