document.write( "Question 1101055: John drove from his house to Kingston in 2 hours. One hour later, he returned hom at a speed 20km/h less than his speed going to Kingston. If John took a total of 6 hours for his trip (including a one hour stop in Kingston), how fast did he travel on each leg of the trip?
\n" ); document.write( "Let speed in km/h going to Kingston be x. \n" ); document.write( "
Algebra.Com's Answer #715677 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
I think Ikleyn and Jorel are interpreting the problem such that:\r
\n" ); document.write( "\n" ); document.write( "The trip to Kingston took 2 hours
\n" ); document.write( "He spent an hour at his destination doing something.
\n" ); document.write( "The problem clearly states, at least now, that the one hour stop is included in the total trip time of 6 hours.
\n" ); document.write( "He took 3 hours traveling back home.
\n" ); document.write( "2+1+3=6
\n" ); document.write( "So Jorel's solution seems right to me.\r
\n" ); document.write( "\n" ); document.write( "If the speed going to Kingston is x, then his speed coming back is x-20. So:
\n" ); document.write( "2(x)= 3(x-20)
\n" ); document.write( "x=60
\n" ); document.write( "His speed going to Kingston was 60 kph; his speed going back was 40 kph\r
\n" ); document.write( "\n" ); document.write( "60 kph is only 37.2823 mph
\n" ); document.write( "40 kph is only 24.8548 mph
\n" ); document.write( "He was out for a Sunday drive in the country.\r
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