document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98407>Question 98407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this asap ! thanks. \r<BR>\n" );
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document.write( "five times the complement of an angle less twice the angle's supplement is 40 degrees. find the measure of the supplement.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71566 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5(90-X)-2(180-X)=40<BR>\n" );
document.write( "450X-5X-360+2X=40<BR>\n" );
document.write( "-3X=40-450+360<BR>\n" );
document.write( "-3X=-50<BR>\n" );
document.write( "X=-50/-3<BR>\n" );
document.write( "X=16.667 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "5(90-16.667)-2(180-16.667)=40<BR>\n" );
document.write( "450-83.333-360+33.33=40<BR>\n" );
document.write( "450+33.333-360-83.333=40<BR>\n" );
document.write( "483.333-443.333=40<BR>\n" );
document.write( "40=40 </SPAN>\n" );
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