document.write( "Question 1101062: Two cyclists, 90 km apart, start riding toward each other at the same time. The speed of one cyclist is twice as fast as the other. Find their speeds if they meet after 2 hours. (use algebra) \n" ); document.write( "
Algebra.Com's Answer #715639 by josmiceli(19441)\"\" \"About 
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Think of this as one of them standing still
\n" ); document.write( "and the other one moving at the sum of their speeds
\n" ); document.write( "Let \"+s+\" = the speed of the slower cyclist
\n" ); document.write( "\"+2s+\" = the speed of the faster cyclist
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "\"+90+=+%28+s+%2B+2s+%29%2A2+\"
\n" ); document.write( "\"+90+=+3s%2A2+\"
\n" ); document.write( "\"+90+=+6s+\"
\n" ); document.write( "\"+s+=+15+\"
\n" ); document.write( "and
\n" ); document.write( "\"+2s+=+30+\"
\n" ); document.write( "----------------
\n" ); document.write( "Their speeds are 15 km/hr and
\n" ); document.write( "30 km/hr
\n" ); document.write( "-----------------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+d%5B1%5D+=+15%2A2+\"
\n" ); document.write( "\"+d%5B1%5D+=+30+\" km
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+30%2A2+\"
\n" ); document.write( "\"+d%5B2%5D+=+60+\" km
\n" ); document.write( "--------------------
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+30+%2B+60+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+90+\" km
\n" ); document.write( "OK
\n" ); document.write( "
\n" );