document.write( "Question 1101057: Amy can run the 100 meter in 6 minutes. Betty can run the 100 meter in 8 minutes. If Betty goes out to practice and starts 1 minutes before Amy starts on her practice, will Amy catch up to Betty before she reaches the 100m marker?
\n" ); document.write( "Let x be the time in minutes for Amy to catch Betty.
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Algebra.Com's Answer #715630 by jorel1380(3719)\"\" \"About 
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100/8=12.5 m/min
\n" ); document.write( "100/6=16.67 m/min
\n" ); document.write( "12.5m+n(12.5)=n(16.67)
\n" ); document.write( "16.67n-12.5n=12.5
\n" ); document.write( "n=3 minutes before Amy catches Betty. Betty will have been running for 4 minutes by that time
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