document.write( "Question 1101031: when 19 is reduced by 1/3 of a number,result is 15. find number \n" ); document.write( "
Algebra.Com's Answer #715601 by ankor@dixie-net.com(22740)\"\" \"About 
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when 19 is reduced by 1/3 of a number,result is 15.
\n" ); document.write( " find number
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\n" ); document.write( "19 - \"1%2F3\"n = 15
\n" ); document.write( "\"-1%2F3\"n = 15 - 19
\n" ); document.write( "\"-1%2F3\"n = -4
\n" ); document.write( "multiply both sides by -3
\n" ); document.write( "n = 12
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\n" ); document.write( "Check in original statement
\n" ); document.write( " 19 - \"1%2F3\"(12) = 15
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