document.write( "Question 1101022: Solve the system:
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document.write( "{ x^2 + y^2 = 50
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document.write( "{ 2x^2 - 3xy + 3y^2 = 50 \n" );
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Algebra.Com's Answer #715586 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! { x^2 + y^2 = 50 \n" ); document.write( "{ 2x^2 - 3xy + 3y^2 = 50 \n" ); document.write( "---------- \n" ); document.write( "y^2 = 50-x^2 \n" ); document.write( "y = sqrt(50-x^2) \n" ); document.write( "Sub for y & y^2 \n" ); document.write( "========= \n" ); document.write( "2x^2 + 3(50-x^2) - 3x*sqrt(50-x^2) = 50 \n" ); document.write( "2x^2 + 150 - 3x^2 - 3x*sqrt(50-x^2) = 50 \n" ); document.write( "x^2 + 3x*sqrt(50-x^2) = 100 \n" ); document.write( "x^2 - 100 = 3x*sqrt(50-x^2) \n" ); document.write( "x^4 - 200x^2 + 10000 = 450x^2 - 9x^4 \n" ); document.write( "10x^4 - 650x^2 + 10000 = 0 \n" ); document.write( "x^4 - 65x^2 + 1000 = 0 \n" ); document.write( "(x^2 - 25)*(x^2 - 40) = 0 \n" ); document.write( "x = +/-5 --> y = +/-5 \n" ); document.write( "-------------- \n" ); document.write( "x = +/-2sqrt(10) --> y = +/-sqrt(10) \n" ); document.write( "Check for extraneous solutions.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |