document.write( "Question 1100931: In PRS, segment PT is an altitude and segment PX is a median.\r
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document.write( "Find RS if RX = x + 7 and SX = 3x – 11\r
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document.write( "Find RT if RT = x – 6 and PTR = 8x - 6 \n" );
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Algebra.Com's Answer #715562 by ikleyn(52788)![]() ![]() You can put this solution on YOUR website! In PRS, segment PT is an altitude and segment PX is a median.\r \n" ); document.write( "\n" ); document.write( "Find RS if RX = x + 7 and SX = 3x – 11\r \n" ); document.write( "\n" ); document.write( "Find RT if RT = x – 6 and PTR = 8x - 6 \n" ); document.write( "~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1. Find RS if RX = x + 7 and SX = 3x – 11 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "a) Make a sketch to follow my arguments.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "b) Since PX is the median, |RT| = |SX| (the measures of these segments are the same).\r\n" ); document.write( "\r\n" ); document.write( " It gives you an equation'\r\n" ); document.write( "\r\n" ); document.write( " x + 7 = 3x - 11 ====> 7 + 11 = 3x - x ====> 2x = 18 ====> x = 9.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Then |RS| = x+7 = 9+7 = 16; |SX| = 3x-11 = 3*9-11 = 16 (it is not amazing: it should be so !)\r\n" ); document.write( "\r\n" ); document.write( " and |RS| = 16 + 16 = 32.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. Find RT if RT = x – 6 and PTR = 8x - 6.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " Honestly, I can not read this: PTR = 8x - 6,\r\n" ); document.write( "\r\n" ); document.write( " and do not understand what does it mean.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In future posts, please do not use this symbol \" \", since it is non-standard and its meaning is dark.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |