document.write( "Question 1100984: Left on together, the cold and hot water faucets of a certain bathtub take
\n" ); document.write( "4
\n" ); document.write( " minutes to fill the tub. If it takes the cold water faucet
\n" ); document.write( "12
\n" ); document.write( " minutes to fill the tub by itself, how long will it take the hot water faucet to fill the tub on its own?
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Algebra.Com's Answer #715546 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "First the standard method of solution, usually taught in beginning algebra classes....

\n" ); document.write( "The two tubs together fill the tub in 4 minutes; so they fill 1/4 of the tub in 1 minute.

\n" ); document.write( "The cold water faucet fills the tub alone in 12 minutes; so it fills 1/12 of the tub in 1 minute.

\n" ); document.write( "So the fraction of the tub that the hot water faucet fills in 1 minute is \"1%2F4+-+1%2F12+=+3%2F12+-+1%2F12+=+2%2F12+=+1%2F6\"

\n" ); document.write( "Since the hot water faucet can fill 1/6 of the tub in 1 minute, it can fill the tub in 6 minutes.

\n" ); document.write( "Algebraically, if x is the number of minutes is takes the hot water faucet to fill the tub alone,
\n" ); document.write( "\"1%2F12+%2B+1%2Fx+=+1%2F4\"
\n" ); document.write( "\"1%2Fx+=+1%2F4+-+1%2F12+=+3%2F12+-+1%2F12+=+2%2F12+=+1%2F6\"
\n" ); document.write( "\"x+=+6\"


\n" ); document.write( "And here is an alternative solution method which I find many students prefer....

\n" ); document.write( "The cold water faucet can fill the tub in 12 minutes.
\n" ); document.write( "In those same 12 minutes, the two faucets together could fill the tub 3 times.
\n" ); document.write( "But if together they can fill the tub 3 times in 12 minutes, and the cold water faucet alone can fill it only 1 time in 12 minutes, then the hot water faucet can fill the tub 2 times in 12 minutes.
\n" ); document.write( "But that means it can fill the tub once in 6 minutes.

\n" ); document.write( "Try both methods for solving this kind of problem and find which \"workd' better for you.
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