document.write( "Question 1100969: Write the quadratic function in vertex form.\r
\n" ); document.write( "\n" ); document.write( "y = x^2 + 16x + 74
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Algebra.Com's Answer #715524 by algebrahouse.com(1659)\"\" \"About 
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Find the x-coordinate of the vertex.
\n" ); document.write( "-b/2a = x-coordinate of vertex\r
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\n" ); document.write( "\n" ); document.write( "y = x² + 16x + 74
\n" ); document.write( "a = 1, b = 16, c = 74\r
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\n" ); document.write( "\n" ); document.write( "-b
\n" ); document.write( "--- = -16/2(1) = -8
\n" ); document.write( "2a\r
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\n" ); document.write( "\n" ); document.write( "x-coordinate of vertex is -8\r
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\n" ); document.write( "\n" ); document.write( "Find the y-coordinate of the vertex by substituting -8 in for x.\r
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\n" ); document.write( "\n" ); document.write( "y = (-8)² + 16(-8) + 74 {substituted -8 in for x}
\n" ); document.write( "y = 64 - 128 + 74 {evaluated exponent and multiplied}
\n" ); document.write( "y = 10 {added and subtracted}\r
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\n" ); document.write( "\n" ); document.write( "Vertex is (-8,10)\r
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\n" ); document.write( "\n" ); document.write( "Vertex form is y = a(x - h)² + k
\n" ); document.write( "(h,k) are the coordinates of the vertex.\r
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\n" ); document.write( "\n" ); document.write( "y = (x - 8)² + 10 {substituted vertex into vertex form}
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For more help from me, visit: www.algebrahouse.com


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