document.write( "Question 1100947: A committee of five people must be selected from five men and eight women. How many different ways can selection be done if there are at least 3 women on the committee? \n" ); document.write( "
Algebra.Com's Answer #715504 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A committee of five people must be selected from five men and eight women. How many different ways can selection be done if there are at least 3 women on the committee? \n" ); document.write( "--- \n" ); document.write( "3 women: 2 men:: 8C3*5C2 = 56*10 = 560 ways \n" ); document.write( "4 women:: 1 man: 8C4*5 = 70*5 = 350 ways \n" ); document.write( "5 women:: 0 men::8C5 = 56 ways \n" ); document.write( "--- \n" ); document.write( "Total = 560+350+56 = 966 ways \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |