document.write( "Question 1100947: A committee of five people must be selected from five men and eight women. How many different ways can selection be done if there are at least 3 women on the committee? \n" ); document.write( "
Algebra.Com's Answer #715504 by stanbon(75887)\"\" \"About 
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A committee of five people must be selected from five men and eight women. How many different ways can selection be done if there are at least 3 women on the committee?
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\n" ); document.write( "3 women: 2 men:: 8C3*5C2 = 56*10 = 560 ways
\n" ); document.write( "4 women:: 1 man: 8C4*5 = 70*5 = 350 ways
\n" ); document.write( "5 women:: 0 men::8C5 = 56 ways
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\n" ); document.write( "Total = 560+350+56 = 966 ways
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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