document.write( "Question 1100883: The owner of a company repair shop has determined that their daily revenue has mean $7200 and a standard deviation $1200. the daily revenue totals for the next 30 days will be monitored. What is the probability that the mean daily revenue for the next 30 days will exceed $7000? \n" ); document.write( "
Algebra.Com's Answer #715482 by Boreal(15235) You can put this solution on YOUR website! this will be greater than z=(xbar-mean)/sigma/sqrt(n) \n" ); document.write( "z>(7000-7200)/(1200/sqrt(30) \n" ); document.write( ">-200*sqrt(30)/1200>-0.91 \n" ); document.write( "This probability is 0.8186. \n" ); document.write( " |