document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98371>Question 98371</A>: <I><SPAN STYLE=\"word-break: break-all;\"> could some one help me graph this linear equation.<BR>\n" );
document.write( "2y+18x=4. thank you very much </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71546 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Re-write the equation in the slope-intercept form (y=mx+b)<BR>\n" );
document.write( "2y+18x=4<BR>\n" );
document.write( "2y+18x-18x=-18x+4<BR>\n" );
document.write( "2y=-18x+4<BR>\n" );
document.write( "2y/2=-18x/2+4/2<BR>\n" );
document.write( "y=-9x+2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Graph using (0,2) as the point where the line crosses the graph(the y-intercept(b) of the line) and a slope of (-9)<BR>\n" );
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