document.write( "Question 1100875: consider that the historical return of an investment follows a normal distribution with a mean of 2000 dollars and a standard deviation of 300 dollars. what is the upper limit for which 60% of all investment return values are located given that the lower limit is at 1450 dollars? \n" ); document.write( "
Algebra.Com's Answer #715404 by stanbon(75887)\"\" \"About 
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consider that the historical return of an investment follows a normal distribution with a mean of 2000 dollars and a standard deviation of 300 dollars. what is the upper limit for which 60% of all investment return values are located given that the lower limit is at 1450 dollars?
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\n" ); document.write( "z(1450) = (1450-2000)/300) = -1.8333
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\n" ); document.write( "Find the area to the left of z = -1.8333
\n" ); document.write( "normalcdf(-100,-1.8333) = 0.0333
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\n" ); document.write( "Add 0.6 to get area to upper limit = 0.6333
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\n" ); document.write( "Find the z-value with a left tail of 0.6333
\n" ); document.write( "invNorm(0.6333) = 0.341
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\n" ); document.write( "Find the corresponding dollar value
\n" ); document.write( "x = 0.341*300+2000 = $2102.24
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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