document.write( "Question 1100850: Assume that a procedure yields a binomial distribution with a trial repeated
\n" ); document.write( "n
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\n" ); document.write( "n=5 times. Use either the binomial probability formula (or technology) to find the probability of
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\n" ); document.write( "4
\n" ); document.write( "k=4 successes given the probability
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\n" ); document.write( "0.76
\n" ); document.write( "p=0.76 of success on a single trial.\r
\n" ); document.write( "\n" ); document.write( "(Report answer accurate to 4 decimal places.)\r
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\n" ); document.write( "P(X=k)=
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Algebra.Com's Answer #715399 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "The number of ways of having 4 of the 5 trials successful is \"5 choose 4\" = 5.

\n" ); document.write( "The probability of any one of those ways is \"%280.76%5E4%29%28%281-0.76%29%5E1%29\".

\n" ); document.write( "Then the probability of 4 successes in 5 tries is
\n" ); document.write( "\"5%2A%280.76%5E4%29%281-0.76%5E1%29+=+.4003\"
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