document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1100780>Question 1100780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a farmer has 800m of fencing material to enclose a rectangular field. the width of the field is 50m less than the length. find the dimensions of the field </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #715336 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=715336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width is x and the length is x+50.<BR>\n" );
document.write( "the perimeter is 2width+2length<BR>\n" );
document.write( "2x+2(x+50)=800<BR>\n" );
document.write( "4x+100=800<BR>\n" );
document.write( "4x=700<BR>\n" );
document.write( "x=175 feet width<BR>\n" );
document.write( "x+50=225 feet length </SPAN>\n" );
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