document.write( "Question 1100324: The woodland jumping frog can hop suprisingly long distances given it’s small size. A long hop can be modeled by y=-2/9x[x-6] how far can a woodland jumping frog hop
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Algebra.Com's Answer #715328 by Boreal(15235)\"\" \"About 
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This is y=-(2/9)(x^2-6x)
\n" ); document.write( "or y=-(2/9)x+(12/9)x
\n" ); document.write( "the x value for the vertex (highest point) is -b/2a or -(12/9)/-(4/9), which is 3 feet. y(3)=-(2/9)(-9)=2 feet ANSWER
\n" ); document.write( "The vertex is symmetrical, so if the starting point is 0 feet, the ending point is 6 feet. ANSWER
\n" ); document.write( "OR y=(-2/9)(x)(x-6)=0
\n" ); document.write( "x=0 and 6.
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